Construct a triangle similar to given triangle ABC with its sides equal to 3/4 of corresponding sides ABC
Construct a triangle similar to given triangle ABC with its sides equal to 3/4 of corresponding sides ABC.
 |
| Required Triangle |
Construction:
- Draw a triangle ABC
- Draw a ray BX, making an acute angle with BC.
- Locate 4 points B1,B2,B3,B4 on BX like that BB1=B1B2=B2B3=B3B4
.
Draw an arc with certain radius from B 
Draw another arc with same radius from B1 
Like that draw 4 arcs 
- Join B4C .
- Draw a line through B3 parallel to B4C intersecting BC at Cl
Draw an arc with certain radius from B4 
With the same radius draw another arc from B3 
Measure the length of arc 
With that length intersect the arc 
- Draw line through Cl parallel to CA to intersect AB at Al
Draw an arc with certain radius from C 
With same radius draw another arc from Cl 
Measure the length of arc 
With that length intersect the arc 
- So AlBlCl is the required triangle.
Post a Comment