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number series 1

NUMBER SERIES

A number series can be considered as a collection of numbers in which all the terms are formed according to some particular rule or all the terms follow a particular pattern. The relation of any term to its proceeding term will be same throughout the series.

  • The relation of any term to its proceeding term will be same throughout the series.
  • We have to find out the rule in which the terms of the series are selected.
  • We have to find out the missing number depending on that rule.

Some types of series

1. Prime Series : In which the terms are the prime numbers in order.

Examples:

(i): 2, 3, 5, 7, 11, 13, . Here the terms of the series are the prime numbers in order. The Prime number after 13 is 17. So, the answer is 17.
(ii): 2, 5, 11,17,23, . This series is by taking the alternative Prime numbers, after 23 the prime numbers are 29 and 31. So, the answer is 31

2. Addition Series : Each number in the series obtained by adding a specific number or series of numbers to previous number.

Examples:

i) 7, 10, 13, 16, 19, 22, Each number is added by 3 to its previous number So, the answer is 22 + 3 = 25.
ii) 10, 14, 19, 25, 32,
number series example So, the answer is 32 + 8 = 40
iii) 5, 7, 10, 15, 22,
number series example
Each number in the series obtained by adding consecutive primes. So, the answer is 22 + 11 = 33.

3. Fibonacci Series : Every third number can be the sum of the preceding two numbers.

Examples:

i) 3, 5, 8, 13, 21, Here starting from third number, 3 + 5 = 8, 5 + 8 = 13, 8 + 13 = 21, So, the answer is 13 + 21 = 34
ii) 6, 10, 16, 26, 42, Here starting from third number, 6 + 10 = 16, 10 + 16 = 26, 16 + 26 = 42, So, the answer is 26 + 42 = 68

4. Difference Series : In which next term is obtained by substracting a fixed number from the previous term.

Example:

i) 87,76,65,54,43,32,? Here, every number is 11 less than the previous number so the answer is 32-11=21.

5. Multiple Series : In which next term is obtained by multiplying a number with the previous term.

Example:

i)3,6,12,24,48,96,? Here, every number is double the previous number so the answer is 96x2=192

6. n² Series :The series formed by Square numbers.

Examples:

i)1,9,25,49,81,? The given series consists of squares of consecutive odd numbers So the next term is 11²= 121.
ii)196,169,144,121,101 find the wrong one. The series is 14²,13²,12²,11²,10² but 10²=100 so, 101 is wrong.

7. n²+1 Series : Each term is a sum of a square and 1.

Example:

i) 5,17,37,65,? This series pattern 2²+1=5,4²+1=17,6²+1=37,8²+1=65 so the answer is 10²+1=101

8. n²-1 Series : Each term is obtained by substracting a from a square number.

Example:

i)0,3,8,15,24,? Series pattern 1n²-1=0,2n²-1=3,3n²-1=8,..... So the answer is 6n²-1=35.

9. n²+n Series : Each term in the series is a sum of a number and its square.

Example:

i)6,12,20,30,42,56,? Series pattern 2²+2,3²+3,4²+4,5²+5,6²+6,7²+7 The answer is 8²+8=72

10. n²-n Series : In which the terms are obtained by sustracting a number from square of that number.

Example:

i) 0,6,12,20,30,42,? Series pattern 2²-2,3²-3,4²-4,5²-5,6²-6,7²-1 So the answer is 8²-8=56

11. n³ Series : The series formed by Cube numbers.

Example:

i) 64,125,216,343,? Series pattern 4³,5³,6³,7³ The answer is 8³= 512.

12. n³+1 Series : Each term is a sum of a cube of a number and 1.

Example:

i) 9,28,65,126,217,? Series pattern 2³+1,3³+1,4³+1,5³+1,6³+1 The answer is 7³+1= 344.

13. n³-1 Series :Each term is obtained by substracting 1 from the cube of a number.

Example:

i) 7,26,63,124,215,342,?. The series is in the form 2³-1,3³-1,4³-1,5³-1,6³-1,7³-1 so the answer is 8³-1=511.

14. n³+n Series : Each term is a sum of a number with its cube.

Example:

i)2,30,130,? Series pattern 1³+1,3³+3,5³+5 The answer is 7³+7=350.

15. n³-n Series : Each term is obtained by substracting 1 from the cube of a number.

Example:

i) 6,24,60,120,? Series pattern 2³-2,3³-3,4³-4,5³-5 The Answer is 6³-6=210

16. Alternating Series : In which the successive terms increase and decrease alternatively.

Examples:

i) 1,4,27,16,125,36,? The given series consists of cubes of odd numbers and squares of even numbers. 1³2²3³4²5³6²7³ So the missing term is 7³=343
ii)1,3,3,6,7,9,13,12,? The given series is combination of two series 1,3,7,13,? and 3,6,9,12 First series followed in +2,+4,+6,+8 So the missing term is 13+8=21